So I’m trying to make a list of numbers that are multiples of 3, this is my code:
multiples_of_3 = []
for value in range(3, 31):
number = value % 3 == 0
multiples_of_3.append(number)
print(multiples_of_3)
But it transforms the results into booleans, which throws me a list with false and trues instead of numbers, what I’m doing wrong? I know comprehension lists exist and that this could be done more efficiently but well, I’m trying to learn and writing it as a comprehension list doesn’t make it easier.
I thought of using an if, but I’m reading a book called “Python Crash Course” and he hasn’t gone over if statements yet, so I thought there has to be a way to express it only using for statements. I have some more knowledge than what was already presented to me in the book from college, but I’m trying to follow the book’s reasoning so far.
In that case, I think you have to use a different approach, and rather than iterate over all the numbers and filter out the ones that aren’t multiples of 3, you can iterate over the multiples of 3 and append every number you iterate over to the array. (Which is what snek_boi’s answer suggests.)
Code for a possible solution, I'm hiding it behind a spoiler because I assume you want to try yourself
multiples_of_3 = [] for value in range(3,31,3): multiples_of_3.append(value) print(multiples_of_3)